22-2(3-x)=10+5x

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Solution for 22-2(3-x)=10+5x equation: 



22-2(3-x)=10+5x

We move all terms to the left:

22-2(3-x)-(10+5x)=0

We add all the numbers together, and all the variables

-2(-1x+3)-(5x+10)+22=0

We multiply parentheses

2x-(5x+10)-6+22=0

We get rid of parentheses

2x-5x-10-6+22=0

We add all the numbers together, and all the variables

-3x+6=0

We move all terms containing x to the left, all other terms to the right

-3x=-6

x=-6/-3

x=+2

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