22-2n=-3(n-5)+2

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Solution for 22-2n=-3(n-5)+2 equation: 



22-2n=-3(n-5)+2

We move all terms to the left:

22-2n-(-3(n-5)+2)=0



We calculate terms in parentheses: -(-3(n-5)+2), so:

-3(n-5)+2

We multiply parentheses

-3n+15+2

We add all the numbers together, and all the variables

-3n+17

Back to the equation:

-(-3n+17)



We get rid of parentheses

-2n+3n-17+22=0

We add all the numbers together, and all the variables

n+5=0

We move all terms containing n to the left, all other terms to the right

n=-5

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