22-2x=2(x+3)

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Solution for 22-2x=2(x+3) equation: 



22-2x=2(x+3)

We move all terms to the left:

22-2x-(2(x+3))=0



We calculate terms in parentheses: -(2(x+3)), so:

2(x+3)

We multiply parentheses

2x+6

Back to the equation:

-(2x+6)



We get rid of parentheses

-2x-2x-6+22=0

We add all the numbers together, and all the variables

-4x+16=0

We move all terms containing x to the left, all other terms to the right

-4x=-16

x=-16/-4

x=+4

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