22-2z=5(z-4)

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Solution for 22-2z=5(z-4) equation: 



22-2z=5(z-4)

We move all terms to the left:

22-2z-(5(z-4))=0



We calculate terms in parentheses: -(5(z-4)), so:

5(z-4)

We multiply parentheses

5z-20

Back to the equation:

-(5z-20)



We get rid of parentheses

-2z-5z+20+22=0

We add all the numbers together, and all the variables

-7z+42=0

We move all terms containing z to the left, all other terms to the right

-7z=-42

z=-42/-7

z=+6

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