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22/24x+3=x
We move all terms to the left:
22/24x+3-(x)=0
Domain of the equation: 24x!=0We add all the numbers together, and all the variables
x!=0/24
x!=0
x∈R
-1x+22/24x+3=0
We multiply all the terms by the denominator
-1x*24x+3*24x+22=0
Wy multiply elements
-24x^2+72x+22=0
a = -24; b = 72; c = +22;
Δ = b2-4ac
Δ = 722-4·(-24)·22
Δ = 7296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{7296}=\sqrt{64*114}=\sqrt{64}*\sqrt{114}=8\sqrt{114}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(72)-8\sqrt{114}}{2*-24}=\frac{-72-8\sqrt{114}}{-48} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(72)+8\sqrt{114}}{2*-24}=\frac{-72+8\sqrt{114}}{-48} $
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