22/4x+1/2x=44

Solution for 22/4x+1/2x=44 equation:

22/4x+1/2x=44

We move all terms to the left:

22/4x+1/2x-(44)=0


Domain of the equation: 4x!=0

x!=0/4

x!=0

x∈R



Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R


We calculate fractions


44x/8x^2+4x/8x^2-44=0

We multiply all the terms by the denominator


44x+4x-44*8x^2=0

We add all the numbers together, and all the variables

48x-44*8x^2=0

Wy multiply elements

-352x^2+48x=0

a = -352; b = 48; c = 0;
Δ = b2-4ac
Δ = 482-4·(-352)·0
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2304}=48$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(48)-48}{2*-352}=\frac{-96}{-704}
=3/22
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(48)+48}{2*-352}=\frac{0}{-704}
=0
$