225=(4+4v)+1

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Solution for 225=(4+4v)+1 equation: 



225=(4+4v)+1

We move all terms to the left:

225-((4+4v)+1)=0

We add all the numbers together, and all the variables

-((4v+4)+1)+225=0



We calculate terms in parentheses: -((4v+4)+1), so:

(4v+4)+1

We get rid of parentheses

4v+4+1

We add all the numbers together, and all the variables

4v+5

Back to the equation:

-(4v+5)



We get rid of parentheses

-4v-5+225=0

We add all the numbers together, and all the variables

-4v+220=0

We move all terms containing v to the left, all other terms to the right

-4v=-220

v=-220/-4

v=+55

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