225=7(4+4v)+1

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Solution for 225=7(4+4v)+1 equation: 



225=7(4+4v)+1

We move all terms to the left:

225-(7(4+4v)+1)=0

We add all the numbers together, and all the variables

-(7(4v+4)+1)+225=0



We calculate terms in parentheses: -(7(4v+4)+1), so:

7(4v+4)+1

We multiply parentheses

28v+28+1

We add all the numbers together, and all the variables

28v+29

Back to the equation:

-(28v+29)



We get rid of parentheses

-28v-29+225=0

We add all the numbers together, and all the variables

-28v+196=0

We move all terms containing v to the left, all other terms to the right

-28v=-196

v=-196/-28

v=+7

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