If it's not what You are looking for type in the equation solver your own equation and let us solve it.
225n^2=1
We move all terms to the left:
225n^2-(1)=0
a = 225; b = 0; c = -1;
Δ = b2-4ac
Δ = 02-4·225·(-1)
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{900}=30$$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-30}{2*225}=\frac{-30}{450} =-1/15 $$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+30}{2*225}=\frac{30}{450} =1/15 $
| 225n2=1 | | x0.30=15.40 | | 34=3(4x-2 | | -7(3x+1)(6x-18)=0 | | 7x=5=2x-5 | | 7x=5=2x-5 | | 7x=5=2x-5 | | 7x=5=2x-5 | | x/8+3=19 | | 7x=5=2x-5 | | 22x22=- | | 22x22=- | | 22x22=- | | 6(x+3=25 | | –2(v+12)=10 | | -1.5x-14=-20 | | -8b=104 | | 2^2*(x+3)+9-5=32 | | v+-9=-6 | | (x-21)^2=28 | | 2w-21=w-3 | | 4+2(2x-3)=4(2x-2)+2 | | v+45=16v | | v+45=16v | | v+45=16v | | v+45=16v | | 0.4x-1.8=7.3 | | v+45=16v | | 0.4x-1.8=7.3 | | 0.4x-1.8=7.3 | | 0.4x-1.8=7.3 | | 2+3=3+2x |