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225x^2-16=33
We move all terms to the left:
225x^2-16-(33)=0
We add all the numbers together, and all the variables
225x^2-49=0
a = 225; b = 0; c = -49;
Δ = b2-4ac
Δ = 02-4·225·(-49)
Δ = 44100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{44100}=210$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-210}{2*225}=\frac{-210}{450} =-7/15 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+210}{2*225}=\frac{210}{450} =7/15 $
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