22=(-x+4)(2x+1)

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Solution for 22=(-x+4)(2x+1) equation:



22=(-x+4)(2x+1)
We move all terms to the left:
22-((-x+4)(2x+1))=0
We add all the numbers together, and all the variables
-((-1x+4)(2x+1))+22=0
We multiply parentheses ..
-((-2x^2-1x+8x+4))+22=0
We calculate terms in parentheses: -((-2x^2-1x+8x+4)), so:
(-2x^2-1x+8x+4)
We get rid of parentheses
-2x^2-1x+8x+4
We add all the numbers together, and all the variables
-2x^2+7x+4
Back to the equation:
-(-2x^2+7x+4)
We get rid of parentheses
2x^2-7x-4+22=0
We add all the numbers together, and all the variables
2x^2-7x+18=0
a = 2; b = -7; c = +18;
Δ = b2-4ac
Δ = -72-4·2·18
Δ = -95
Delta is less than zero, so there is no solution for the equation

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