22=(-x+4)(2x+1)

Solution for 22=(-x+4)(2x+1) equation:

22=(-x+4)(2x+1)

We move all terms to the left:

22-((-x+4)(2x+1))=0

We add all the numbers together, and all the variables

-((-1x+4)(2x+1))+22=0

We multiply parentheses ..

-((-2x^2-1x+8x+4))+22=0


We calculate terms in parentheses: -((-2x^2-1x+8x+4)), so:

(-2x^2-1x+8x+4)

We get rid of parentheses

-2x^2-1x+8x+4

We add all the numbers together, and all the variables

-2x^2+7x+4

Back to the equation:

-(-2x^2+7x+4)


We get rid of parentheses

2x^2-7x-4+22=0

We add all the numbers together, and all the variables

2x^2-7x+18=0

a = 2; b = -7; c = +18;
Δ = b2-4ac
Δ = -72-4·2·18
Δ = -95
Delta is less than zero, so there is no solution for the equation