22=(4/x-3)+4x

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Solution for 22=(4/x-3)+4x equation: 



22=(4/x-3)+4x

We move all terms to the left:

22-((4/x-3)+4x)=0



Domain of the equation: x-3)+4x)!=0

x∈R



We multiply all the terms by the denominator


-((4+22*x-3)+4x)=0



We calculate terms in parentheses: -((4+22*x-3)+4x), so:

(4+22*x-3)+4x

We add all the numbers together, and all the variables

(22x+1)+4x

We add all the numbers together, and all the variables

4x+(22x+1)

We get rid of parentheses

4x+22x+1

We add all the numbers together, and all the variables

26x+1

Back to the equation:

-(26x+1)



We get rid of parentheses

-26x-1=0

We move all terms containing x to the left, all other terms to the right

-26x=1

x=1/-26

x=-1/26

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