22=(9/5)(c+32)

Solution for 22=(9/5)(c+32) equation:

22=(9/5)(c+32)

We move all terms to the left:

22-((9/5)(c+32))=0


Domain of the equation: 5)(c+32))!=0

c∈R


We add all the numbers together, and all the variables

-((+9/5)(c+32))+22=0

We multiply parentheses ..

-((+9c^2+9/5*32))+22=0

We multiply all the terms by the denominator


-((+9c^2+9+22*5*32))=0


We calculate terms in parentheses: -((+9c^2+9+22*5*32)), so:

(+9c^2+9+22*5*32)

We get rid of parentheses

9c^2+9+22*5*32

We add all the numbers together, and all the variables

9c^2+3529

Back to the equation:

-(9c^2+3529)


We get rid of parentheses

-9c^2-3529=0

a = -9; b = 0; c = -3529;
Δ = b2-4ac
Δ = 02-4·(-9)·(-3529)
Δ = -127044
Delta is less than zero, so there is no solution for the equation