22=-7(n-2)+3n

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Solution for 22=-7(n-2)+3n equation: 



22=-7(n-2)+3n

We move all terms to the left:

22-(-7(n-2)+3n)=0



We calculate terms in parentheses: -(-7(n-2)+3n), so:

-7(n-2)+3n

We add all the numbers together, and all the variables

3n-7(n-2)

We multiply parentheses

3n-7n+14

We add all the numbers together, and all the variables

-4n+14

Back to the equation:

-(-4n+14)



We get rid of parentheses

4n-14+22=0

We add all the numbers together, and all the variables

4n+8=0

We move all terms containing n to the left, all other terms to the right

4n=-8

n=-8/4

n=-2

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