22=1/2(2y-4)-y

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Solution for 22=1/2(2y-4)-y equation: 



22=1/2(2y-4)-y

We move all terms to the left:

22-(1/2(2y-4)-y)=0



Domain of the equation: 2(2y-4)-y)!=0

y∈R



We multiply all the terms by the denominator


-(1+22*2(2y-4)-y)=0



We calculate terms in parentheses: -(1+22*2(2y-4)-y), so:

1+22*2(2y-4)-y

determiningTheFunctionDomain
22*2(2y-4)-y+1

We add all the numbers together, and all the variables

-1y+22*2(2y-4)+1

Wy multiply elements

-1y+44y(2+1

Back to the equation:

-(-1y+44y(2+1)



We add all the numbers together, and all the variables

-(-1y+44y3=0

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