22=1/2(6)(2x+3x)

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Solution for 22=1/2(6)(2x+3x) equation:



22=1/2(6)(2x+3x)
We move all terms to the left:
22-(1/2(6)(2x+3x))=0
Domain of the equation: 26(2x+3x))!=0
x∈R
We add all the numbers together, and all the variables
-(1/26(+5x))+22=0
We multiply all the terms by the denominator
-(1+22*26(+5x))=0
We calculate terms in parentheses: -(1+22*26(+5x)), so:
1+22*26(+5x)
determiningTheFunctionDomain 22*26(+5x)+1
Wy multiply elements
572x(++1
We use the square of the difference formula
572x(+1
Back to the equation:
-(572x(+1)
We add all the numbers together, and all the variables
-(572x1=0

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