22=1/2(x+3+4x+1)

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Solution for 22=1/2(x+3+4x+1) equation: 



22=1/2(x+3+4x+1)

We move all terms to the left:

22-(1/2(x+3+4x+1))=0



Domain of the equation: 2(x+3+4x+1))!=0

x∈R



We add all the numbers together, and all the variables

-(1/2(5x+4))+22=0

We multiply all the terms by the denominator


-(1+22*2(5x+4))=0



We calculate terms in parentheses: -(1+22*2(5x+4)), so:

1+22*2(5x+4)

determiningTheFunctionDomain
22*2(5x+4)+1

Wy multiply elements

44x(5+1

Back to the equation:

-(44x(5+1)



We add all the numbers together, and all the variables

-(44x6=0

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