22=2(12+z)

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Solution for 22=2(12+z) equation: 



22=2(12+z)

We move all terms to the left:

22-(2(12+z))=0

We add all the numbers together, and all the variables

-(2(z+12))+22=0



We calculate terms in parentheses: -(2(z+12)), so:

2(z+12)

We multiply parentheses

2z+24

Back to the equation:

-(2z+24)



We get rid of parentheses

-2z-24+22=0

We add all the numbers together, and all the variables

-2z-2=0

We move all terms containing z to the left, all other terms to the right

-2z=2

z=2/-2

z=-1

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