22=2(2x-4)+2

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Solution for 22=2(2x-4)+2 equation: 



22=2(2x-4)+2

We move all terms to the left:

22-(2(2x-4)+2)=0



We calculate terms in parentheses: -(2(2x-4)+2), so:

2(2x-4)+2

We multiply parentheses

4x-8+2

We add all the numbers together, and all the variables

4x-6

Back to the equation:

-(4x-6)



We get rid of parentheses

-4x+6+22=0

We add all the numbers together, and all the variables

-4x+28=0

We move all terms containing x to the left, all other terms to the right

-4x=-28

x=-28/-4

x=+7

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