22=3(3z+11)-z

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Solution for 22=3(3z+11)-z equation: 



22=3(3z+11)-z

We move all terms to the left:

22-(3(3z+11)-z)=0



We calculate terms in parentheses: -(3(3z+11)-z), so:

3(3z+11)-z

We add all the numbers together, and all the variables

-1z+3(3z+11)

We multiply parentheses

-1z+9z+33

We add all the numbers together, and all the variables

8z+33

Back to the equation:

-(8z+33)



We get rid of parentheses

-8z-33+22=0

We add all the numbers together, and all the variables

-8z-11=0

We move all terms containing z to the left, all other terms to the right

-8z=11

z=11/-8

z=-1+3/8

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