22=4(y-5)+2y

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Solution for 22=4(y-5)+2y equation:



22=4(y-5)+2y
We move all terms to the left:
22-(4(y-5)+2y)=0
We calculate terms in parentheses: -(4(y-5)+2y), so:
4(y-5)+2y
We add all the numbers together, and all the variables
2y+4(y-5)
We multiply parentheses
2y+4y-20
We add all the numbers together, and all the variables
6y-20
Back to the equation:
-(6y-20)
We get rid of parentheses
-6y+20+22=0
We add all the numbers together, and all the variables
-6y+42=0
We move all terms containing y to the left, all other terms to the right
-6y=-42
y=-42/-6
y=+7

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