22=5(-8+10x)+9(10-4x)

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Solution for 22=5(-8+10x)+9(10-4x) equation: 



22=5(-8+10x)+9(10-4x)

We move all terms to the left:

22-(5(-8+10x)+9(10-4x))=0

We add all the numbers together, and all the variables

-(5(10x-8)+9(-4x+10))+22=0



We calculate terms in parentheses: -(5(10x-8)+9(-4x+10)), so:

5(10x-8)+9(-4x+10)

We multiply parentheses

50x-36x-40+90

We add all the numbers together, and all the variables

14x+50

Back to the equation:

-(14x+50)



We get rid of parentheses

-14x-50+22=0

We add all the numbers together, and all the variables

-14x-28=0

We move all terms containing x to the left, all other terms to the right

-14x=28

x=28/-14

x=-2

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