22=5(v+2)-2v

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Solution for 22=5(v+2)-2v equation: 



22=5(v+2)-2v

We move all terms to the left:

22-(5(v+2)-2v)=0



We calculate terms in parentheses: -(5(v+2)-2v), so:

5(v+2)-2v

We add all the numbers together, and all the variables

-2v+5(v+2)

We multiply parentheses

-2v+5v+10

We add all the numbers together, and all the variables

3v+10

Back to the equation:

-(3v+10)



We get rid of parentheses

-3v-10+22=0

We add all the numbers together, and all the variables

-3v+12=0

We move all terms containing v to the left, all other terms to the right

-3v=-12

v=-12/-3

v=+4

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