22=5+2(t+4)

Solution for 22=5+2(t+4) equation:

22=5+2(t+4)

We move all terms to the left:

22-(5+2(t+4))=0


We calculate terms in parentheses: -(5+2(t+4)), so:

5+2(t+4)

determiningTheFunctionDomain
2(t+4)+5

We multiply parentheses

2t+8+5

We add all the numbers together, and all the variables

2t+13

Back to the equation:

-(2t+13)


We get rid of parentheses

-2t-13+22=0

We add all the numbers together, and all the variables

-2t+9=0

We move all terms containing t to the left, all other terms to the right

-2t=-9

t=-9/-2

t=4+1/2