22=6(v+4)-8v

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Solution for 22=6(v+4)-8v equation: 



22=6(v+4)-8v

We move all terms to the left:

22-(6(v+4)-8v)=0



We calculate terms in parentheses: -(6(v+4)-8v), so:

6(v+4)-8v

We add all the numbers together, and all the variables

-8v+6(v+4)

We multiply parentheses

-8v+6v+24

We add all the numbers together, and all the variables

-2v+24

Back to the equation:

-(-2v+24)



We get rid of parentheses

2v-24+22=0

We add all the numbers together, and all the variables

2v-2=0

We move all terms containing v to the left, all other terms to the right

2v=2

v=2/2

v=1

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