22=6(v+7)+4v

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Solution for 22=6(v+7)+4v equation:



22=6(v+7)+4v
We move all terms to the left:
22-(6(v+7)+4v)=0
We calculate terms in parentheses: -(6(v+7)+4v), so:
6(v+7)+4v
We add all the numbers together, and all the variables
4v+6(v+7)
We multiply parentheses
4v+6v+42
We add all the numbers together, and all the variables
10v+42
Back to the equation:
-(10v+42)
We get rid of parentheses
-10v-42+22=0
We add all the numbers together, and all the variables
-10v-20=0
We move all terms containing v to the left, all other terms to the right
-10v=20
v=20/-10
v=-2

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