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22=60/y2
We move all terms to the left:
22-(60/y2)=0
Domain of the equation: y2)!=0We add all the numbers together, and all the variables
y!=0/1
y!=0
y∈R
-(+60/y2)+22=0
We get rid of parentheses
-60/y2+22=0
We multiply all the terms by the denominator
22*y2-60=0
We add all the numbers together, and all the variables
22y^2-60=0
a = 22; b = 0; c = -60;
Δ = b2-4ac
Δ = 02-4·22·(-60)
Δ = 5280
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{5280}=\sqrt{16*330}=\sqrt{16}*\sqrt{330}=4\sqrt{330}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{330}}{2*22}=\frac{0-4\sqrt{330}}{44} =-\frac{4\sqrt{330}}{44} =-\frac{\sqrt{330}}{11} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{330}}{2*22}=\frac{0+4\sqrt{330}}{44} =\frac{4\sqrt{330}}{44} =\frac{\sqrt{330}}{11} $
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