22=7(-6+2x)-(x+4)

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Solution for 22=7(-6+2x)-(x+4) equation: 



22=7(-6+2x)-(x+4)

We move all terms to the left:

22-(7(-6+2x)-(x+4))=0

We add all the numbers together, and all the variables

-(7(2x-6)-(x+4))+22=0



We calculate terms in parentheses: -(7(2x-6)-(x+4)), so:

7(2x-6)-(x+4)

We multiply parentheses

14x-(x+4)-42

We get rid of parentheses

14x-x-4-42

We add all the numbers together, and all the variables

13x-46

Back to the equation:

-(13x-46)



We get rid of parentheses

-13x+46+22=0

We add all the numbers together, and all the variables

-13x+68=0

We move all terms containing x to the left, all other terms to the right

-13x=-68

x=-68/-13

x=5+3/13

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