22=7(2x-5)+29

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Solution for 22=7(2x-5)+29 equation: 



22=7(2x-5)+29

We move all terms to the left:

22-(7(2x-5)+29)=0



We calculate terms in parentheses: -(7(2x-5)+29), so:

7(2x-5)+29

We multiply parentheses

14x-35+29

We add all the numbers together, and all the variables

14x-6

Back to the equation:

-(14x-6)



We get rid of parentheses

-14x+6+22=0

We add all the numbers together, and all the variables

-14x+28=0

We move all terms containing x to the left, all other terms to the right

-14x=-28

x=-28/-14

x=+2

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