22=8(u-6)+2u

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Solution for 22=8(u-6)+2u equation: 



22=8(u-6)+2u

We move all terms to the left:

22-(8(u-6)+2u)=0



We calculate terms in parentheses: -(8(u-6)+2u), so:

8(u-6)+2u

We add all the numbers together, and all the variables

2u+8(u-6)

We multiply parentheses

2u+8u-48

We add all the numbers together, and all the variables

10u-48

Back to the equation:

-(10u-48)



We get rid of parentheses

-10u+48+22=0

We add all the numbers together, and all the variables

-10u+70=0

We move all terms containing u to the left, all other terms to the right

-10u=-70

u=-70/-10

u=+7

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