22=8(v+2)-2v

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Solution for 22=8(v+2)-2v equation: 



22=8(v+2)-2v

We move all terms to the left:

22-(8(v+2)-2v)=0



We calculate terms in parentheses: -(8(v+2)-2v), so:

8(v+2)-2v

We add all the numbers together, and all the variables

-2v+8(v+2)

We multiply parentheses

-2v+8v+16

We add all the numbers together, and all the variables

6v+16

Back to the equation:

-(6v+16)



We get rid of parentheses

-6v-16+22=0

We add all the numbers together, and all the variables

-6v+6=0

We move all terms containing v to the left, all other terms to the right

-6v=-6

v=-6/-6

v=1

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