22k-12=11(2k-2)+10

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Solution for 22k-12=11(2k-2)+10 equation: 



22k-12=11(2k-2)+10

We move all terms to the left:

22k-12-(11(2k-2)+10)=0



We calculate terms in parentheses: -(11(2k-2)+10), so:

11(2k-2)+10

We multiply parentheses

22k-22+10

We add all the numbers together, and all the variables

22k-12

Back to the equation:

-(22k-12)



We get rid of parentheses

22k-22k+12-12=0

We add all the numbers together, and all the variables

=0

k=0/1

k=0

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