22x+440=2

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Solution for 22x+440=2 equation: 



22x+440=2

We move all terms to the left:

22x+440-(2)=0

We add all the numbers together, and all the variables

22x+438=0

We move all terms containing x to the left, all other terms to the right

22x=-438

x=-438/22

x=-19+10/11

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