22x-21=5(3x-4)+7x-1

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Solution for 22x-21=5(3x-4)+7x-1 equation:



22x-21=5(3x-4)+7x-1
We move all terms to the left:
22x-21-(5(3x-4)+7x-1)=0
We calculate terms in parentheses: -(5(3x-4)+7x-1), so:
5(3x-4)+7x-1
We add all the numbers together, and all the variables
7x+5(3x-4)-1
We multiply parentheses
7x+15x-20-1
We add all the numbers together, and all the variables
22x-21
Back to the equation:
-(22x-21)
We get rid of parentheses
22x-22x+21-21=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0

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