22x-22=3(5x-5)+2x=7

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Solution for 22x-22=3(5x-5)+2x=7 equation: 



22x-22=3(5x-5)+2x=7

We move all terms to the left:

22x-22-(3(5x-5)+2x)=0



We calculate terms in parentheses: -(3(5x-5)+2x), so:

3(5x-5)+2x

We add all the numbers together, and all the variables

2x+3(5x-5)

We multiply parentheses

2x+15x-15

We add all the numbers together, and all the variables

17x-15

Back to the equation:

-(17x-15)



We get rid of parentheses

22x-17x+15-22=0

We add all the numbers together, and all the variables

5x-7=0

We move all terms containing x to the left, all other terms to the right

5x=7

x=7/5

x=1+2/5

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