22x-28=4(3x-2)

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Solution for 22x-28=4(3x-2) equation: 



22x-28=4(3x-2)

We move all terms to the left:

22x-28-(4(3x-2))=0



We calculate terms in parentheses: -(4(3x-2)), so:

4(3x-2)

We multiply parentheses

12x-8

Back to the equation:

-(12x-8)



We get rid of parentheses

22x-12x+8-28=0

We add all the numbers together, and all the variables

10x-20=0

We move all terms containing x to the left, all other terms to the right

10x=20

x=20/10

x=2

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