22x-2=3(x-1)-5(6-2x)

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Solution for 22x-2=3(x-1)-5(6-2x) equation:



22x-2=3(x-1)-5(6-2x)
We move all terms to the left:
22x-2-(3(x-1)-5(6-2x))=0
We add all the numbers together, and all the variables
22x-(3(x-1)-5(-2x+6))-2=0
We calculate terms in parentheses: -(3(x-1)-5(-2x+6)), so:
3(x-1)-5(-2x+6)
We multiply parentheses
3x+10x-3-30
We add all the numbers together, and all the variables
13x-33
Back to the equation:
-(13x-33)
We get rid of parentheses
22x-13x+33-2=0
We add all the numbers together, and all the variables
9x+31=0
We move all terms containing x to the left, all other terms to the right
9x=-31
x=-31/9
x=-3+4/9

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