22x-4-18x=2(2x-3)+2

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Solution for 22x-4-18x=2(2x-3)+2 equation: 



22x-4-18x=2(2x-3)+2

We move all terms to the left:

22x-4-18x-(2(2x-3)+2)=0

We add all the numbers together, and all the variables

4x-(2(2x-3)+2)-4=0



We calculate terms in parentheses: -(2(2x-3)+2), so:

2(2x-3)+2

We multiply parentheses

4x-6+2

We add all the numbers together, and all the variables

4x-4

Back to the equation:

-(4x-4)



We get rid of parentheses

4x-4x+4-4=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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