22x-5=3(6x-4)+4x+7

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Solution for 22x-5=3(6x-4)+4x+7 equation: 



22x-5=3(6x-4)+4x+7

We move all terms to the left:

22x-5-(3(6x-4)+4x+7)=0



We calculate terms in parentheses: -(3(6x-4)+4x+7), so:

3(6x-4)+4x+7

We add all the numbers together, and all the variables

4x+3(6x-4)+7

We multiply parentheses

4x+18x-12+7

We add all the numbers together, and all the variables

22x-5

Back to the equation:

-(22x-5)



We get rid of parentheses

22x-22x+5-5=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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