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22x^2+9=75
We move all terms to the left:
22x^2+9-(75)=0
We add all the numbers together, and all the variables
22x^2-66=0
a = 22; b = 0; c = -66;
Δ = b2-4ac
Δ = 02-4·22·(-66)
Δ = 5808
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{5808}=\sqrt{1936*3}=\sqrt{1936}*\sqrt{3}=44\sqrt{3}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-44\sqrt{3}}{2*22}=\frac{0-44\sqrt{3}}{44} =-\frac{44\sqrt{3}}{44} =-\sqrt{3} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+44\sqrt{3}}{2*22}=\frac{0+44\sqrt{3}}{44} =\frac{44\sqrt{3}}{44} =\sqrt{3} $
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