22x=2x(2+x)

Solution for 22x=2x(2+x) equation:

22x=2x(2+x)

We move all terms to the left:

22x-(2x(2+x))=0

We add all the numbers together, and all the variables

22x-(2x(x+2))=0


We calculate terms in parentheses: -(2x(x+2)), so:

2x(x+2)

We multiply parentheses

2x^2+4x

Back to the equation:

-(2x^2+4x)


We get rid of parentheses

-2x^2+22x-4x=0

We add all the numbers together, and all the variables

-2x^2+18x=0

a = -2; b = 18; c = 0;
Δ = b2-4ac
Δ = 182-4·(-2)·0
Δ = 324
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{324}=18$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(18)-18}{2*-2}=\frac{-36}{-4}
=+9
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(18)+18}{2*-2}=\frac{0}{-4}
=0
$