23(c-1)+2(3c+1)=-(3c+1)

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Solution for 23(c-1)+2(3c+1)=-(3c+1) equation: 



23(c-1)+2(3c+1)=-(3c+1)

We move all terms to the left:

23(c-1)+2(3c+1)-(-(3c+1))=0

We multiply parentheses

23c+6c-(-(3c+1))-23+2=0



We calculate terms in parentheses: -(-(3c+1)), so:

-(3c+1)

We get rid of parentheses

-3c-1

Back to the equation:

-(-3c-1)



We add all the numbers together, and all the variables

29c-(-3c-1)-21=0

We get rid of parentheses

29c+3c+1-21=0

We add all the numbers together, and all the variables

32c-20=0

We move all terms containing c to the left, all other terms to the right

32c=20

c=20/32

c=5/8

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