23(x+2)=3(x-23)

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Solution for 23(x+2)=3(x-23) equation: 



23(x+2)=3(x-23)

We move all terms to the left:

23(x+2)-(3(x-23))=0

We multiply parentheses

23x-(3(x-23))+46=0



We calculate terms in parentheses: -(3(x-23)), so:

3(x-23)

We multiply parentheses

3x-69

Back to the equation:

-(3x-69)



We get rid of parentheses

23x-3x+69+46=0

We add all the numbers together, and all the variables

20x+115=0

We move all terms containing x to the left, all other terms to the right

20x=-115

x=-115/20

x=-5+3/4

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