23+2x-7=2(x+4)-3

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Solution for 23+2x-7=2(x+4)-3 equation: 



23+2x-7=2(x+4)-3

We move all terms to the left:

23+2x-7-(2(x+4)-3)=0

We add all the numbers together, and all the variables

2x-(2(x+4)-3)+16=0



We calculate terms in parentheses: -(2(x+4)-3), so:

2(x+4)-3

We multiply parentheses

2x+8-3

We add all the numbers together, and all the variables

2x+5

Back to the equation:

-(2x+5)



We get rid of parentheses

2x-2x-5+16=0

We add all the numbers together, and all the variables

11!=0

There is no solution for this equation

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