23+3(2x-3)-3=-7(x+1)+4

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Solution for 23+3(2x-3)-3=-7(x+1)+4 equation: 



23+3(2x-3)-3=-7(x+1)+4

We move all terms to the left:

23+3(2x-3)-3-(-7(x+1)+4)=0

We add all the numbers together, and all the variables

3(2x-3)-(-7(x+1)+4)+20=0

We multiply parentheses

6x-(-7(x+1)+4)-9+20=0



We calculate terms in parentheses: -(-7(x+1)+4), so:

-7(x+1)+4

We multiply parentheses

-7x-7+4

We add all the numbers together, and all the variables

-7x-3

Back to the equation:

-(-7x-3)



We add all the numbers together, and all the variables

6x-(-7x-3)+11=0

We get rid of parentheses

6x+7x+3+11=0

We add all the numbers together, and all the variables

13x+14=0

We move all terms containing x to the left, all other terms to the right

13x=-14

x=-14/13

x=-1+1/13

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