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23+4(n-2)=9n+5(3+n)
We move all terms to the left:
23+4(n-2)-(9n+5(3+n))=0
We add all the numbers together, and all the variables
4(n-2)-(9n+5(n+3))+23=0
We multiply parentheses
4n-(9n+5(n+3))-8+23=0
We calculate terms in parentheses: -(9n+5(n+3)), so:We add all the numbers together, and all the variables
9n+5(n+3)
We multiply parentheses
9n+5n+15
We add all the numbers together, and all the variables
14n+15
Back to the equation:
-(14n+15)
4n-(14n+15)+15=0
We get rid of parentheses
4n-14n-15+15=0
We add all the numbers together, and all the variables
-10n=0
n=0/-10
n=0
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