23+4(n-2)=9n+5(3+n)

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Solution for 23+4(n-2)=9n+5(3+n) equation: 



23+4(n-2)=9n+5(3+n)

We move all terms to the left:

23+4(n-2)-(9n+5(3+n))=0

We add all the numbers together, and all the variables

4(n-2)-(9n+5(n+3))+23=0

We multiply parentheses

4n-(9n+5(n+3))-8+23=0



We calculate terms in parentheses: -(9n+5(n+3)), so:

9n+5(n+3)

We multiply parentheses

9n+5n+15

We add all the numbers together, and all the variables

14n+15

Back to the equation:

-(14n+15)



We add all the numbers together, and all the variables

4n-(14n+15)+15=0

We get rid of parentheses

4n-14n-15+15=0

We add all the numbers together, and all the variables

-10n=0

n=0/-10

n=0

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