23+4n=2(1+4n)+1

Solution for 23+4n=2(1+4n)+1 equation:

23+4n=2(1+4n)+1

We move all terms to the left:

23+4n-(2(1+4n)+1)=0

We add all the numbers together, and all the variables

4n-(2(4n+1)+1)+23=0


We calculate terms in parentheses: -(2(4n+1)+1), so:

2(4n+1)+1

We multiply parentheses

8n+2+1

We add all the numbers together, and all the variables

8n+3

Back to the equation:

-(8n+3)


We get rid of parentheses

4n-8n-3+23=0

We add all the numbers together, and all the variables

-4n+20=0

We move all terms containing n to the left, all other terms to the right

-4n=-20

n=-20/-4

n=+5