23+4n=2(1+4n)1

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Solution for 23+4n=2(1+4n)1 equation: 



23+4n=2(1+4n)1

We move all terms to the left:

23+4n-(2(1+4n)1)=0

We add all the numbers together, and all the variables

4n-(2(4n+1)1)+23=0



We calculate terms in parentheses: -(2(4n+1)1), so:

2(4n+1)1

We multiply parentheses

8n+2

Back to the equation:

-(8n+2)



We get rid of parentheses

4n-8n-2+23=0

We add all the numbers together, and all the variables

-4n+21=0

We move all terms containing n to the left, all other terms to the right

-4n=-21

n=-21/-4

n=5+1/4

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