23-(2c=3)=2(c=5)+c

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Solution for 23-(2c=3)=2(c=5)+c equation: 



23-(2c=3)=2(c=5)+c

We move all terms to the left:

23-(2c-(3))=0

We get rid of parentheses

-2c+3+23=0

We add all the numbers together, and all the variables

-2c+26=0

We move all terms containing c to the left, all other terms to the right

-2c=-26

c=-26/-2

c=+13

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