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23-(2x+5)=3(x+2)+x
We move all terms to the left:
23-(2x+5)-(3(x+2)+x)=0
We get rid of parentheses
-2x-(3(x+2)+x)-5+23=0
We calculate terms in parentheses: -(3(x+2)+x), so:We add all the numbers together, and all the variables
3(x+2)+x
We add all the numbers together, and all the variables
x+3(x+2)
We multiply parentheses
x+3x+6
We add all the numbers together, and all the variables
4x+6
Back to the equation:
-(4x+6)
-2x-(4x+6)+18=0
We get rid of parentheses
-2x-4x-6+18=0
We add all the numbers together, and all the variables
-6x+12=0
We move all terms containing x to the left, all other terms to the right
-6x=-12
x=-12/-6
x=+2
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